retagged by
989 views

4 Answers

Best answer
1 votes
1 votes
@Srestha,look I worked out the example as per your suggestion.

Now to the same ques goes 3 answers.

Let the no's be 2x+1,2x+3,2x+5 respectively.So,

  3(2x+1)=2(2x+5)+3

6x+3=4x+10+3

2x=10. x=5. And we want the third no therefore, (2x+5)=2*5+5=15.

Hence,15.
selected by
3 votes
3 votes
Let the three consecutive odd numbers be X, X+2,  X+4

According to question, equation will be: 3(X) = 3 + 2(X+4)

                                                             X=11

hence,third integer = X + 4 = 11 + 4 =15

option A will be correct.
edited by
0 votes
0 votes
Let the first three consecutive odd integers be x,x+2,x+4. So as per question,

3x=2(x+4)+3

3x=2x+8+3

3x-2x=11

Hence, x=11.

So the third integer is x+4=11+4=15.

This is how we arrive at the answer 15.
0 votes
0 votes
we can consider the odd numbers as 1,3,5 so accordingly the terms will be x,x+2,x+4
3x=3+2*(x+4) so x=11
third term is 11+4=15

Related questions

1 votes
1 votes
2 answers
2
sid1221 asked May 23, 2018
1,730 views
In an infinite geometric progression ,each term is equal to $2$ times the sum of the terms that follow . If the first term of the series is $8$ ,find the sum of the serie...
0 votes
0 votes
2 answers
3
moin asked Sep 30, 2017
721 views
answer is A please explain
0 votes
0 votes
0 answers
4
moin asked Sep 30, 2017
216 views
answer is A please explain