#PROG

Question

Assume that the size of char is 1 byte and negatives are stored in 2's complement form

#include<stdio.h> int main() {     char c = 125;     c = c+10;     printf("%d", c);     return 0; }

1.135

2.+INF

3.-121

4.-8

Answer 1

Binary form of 125=>01111101

Binary form of 10=>00001010

125+10=10000111    // this is a negative number because sign bit is one

take 2's complement of 10000111 is 01111001

decimal value of 01111001 is 121

so answer is =-121

Comments

One more interesting.

#include <stdio.h>
int main() {
    char c = 125;
    c = c+10;
    printf("%u",c);
    return 0;
}

---

gives the address of c