58.a)solve the given recurrence relation ?
$a_{n}=3a_{n/2}+n$
n=2^k , $a_{1}$=1
by changing the variables $b_{k}=3b_{k-1}+2^{k}$
after solving this i got c1.$3^{k}-2.2^{k}$
now i am facing difficulty to find the value of c1 ... might be silly can some one help me