Register

Discrete maths equivalence relation

483 views
0 votes
0 votes
Consider the equivalence relation
namely, R = (x, y) I x - y is an integer}.

 What is the equivalence class of R={ (x,y) | x-y in integer(Z)}  equivalence
relation?

Given answer is :- (n + 1/2 I n E Z)

My answer is :- (n*1/2 | n E Z)

 

Is my answer correct also?
User Avatar

Please log in or register to answer this question.

Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

0 votes
0 votes
1 answer
1
RahulVerma3 asked Mar 30
74 views
Discrete Mathematics | Relations | Equivalence relation |
The relation R on the set {(a, b) |a, b € Z} where (a, b)R(c, d) means a = c or b = d. Is R a equivalence relation or not ?
The relation R on the set {(a, b) |a, b € Z} where (a, b)R(c, d) means a = c or b = d. Is R a equivalence relation or not ?
User Avatar
0 votes
0 votes
0 answers
2
Shubhanshu asked Nov 15, 2017
459 views
Equivalence Relation
Which of the above are true. I think only 1st one is true. But the answer given is all are true.
Which of the above are true.I think only 1st one is true. But the answer given is all are true.
User Avatar
4 votes
4 votes
1 answer
3
Hemant Parihar asked Sep 2, 2017
1,564 views
Equivalence and Inverse of Relation.
Proof the following statement. 1. If R1 and R2 are the equivalence relation on X then R1 $\cap$ $R2^{-1}$ (Inverse of R2) is also an equivalence relation. 2. If R is reflexive and transitive relation on X then R $\cap$ $R^{-1}$ is an equivalence relation.
Proof the following statement.1. If R1 and R2 are the equivalence relation on X then R1 $\cap$ $R2^{-1}$ (Inverse of R2) is also an equivalence relation.2. If R is reflex...
User Avatar
Link Copied!