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cSO,4 FFs required.

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4 FF required

Read the output at the two rightmost FF.

It is same as a mod 7 counter with sequence of

0->1->4->6->8->11->13->0

The only difference is that you are reading the output on the two rightmost flip flops (L.S.B side ).
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000 = 0

101 = 5

100 = 4

010 = 2

100 = 4

011= 3

001 = 1

above sequence are not proper differentiate with help of 3 bit because 4 & 4 are matched then apply similarly method for 4 bit

0000 = 0

0101 = 5

0100 = 4

0010 = 2

1100 = 12

0011= 3

0001 = 1

our state will be different

minimum number of bit 4

we know that no of flip flop =  no of bit    4 flip flop recquired

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