4 votes 4 votes If the group has 40 elements and it has two subgroups namely h and k with order 10 and 20 then what can't be order of (h intersection k) a:)10 b:)20 c:)3 d:)1 e:) 4 My answer is both c and b and e. Is it correct? Mathematical Logic discrete-mathematics group-theory + – rahul sharma 5 asked Jun 15, 2017 edited Jun 15, 2017 by rahul sharma 5 rahul sharma 5 1.1k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes I think only OPTION C can't be possible as 3 is not be he divisor of 40. junaid ahmad answered Jun 15, 2017 junaid ahmad comment Share Follow See all 6 Comments See all 6 6 Comments reply Show 3 previous comments junaid ahmad commented Jun 15, 2017 reply Follow Share How 20 element can come in to intersection of two sets having 20 and 10 elements think! 1 votes 1 votes rahul sharma 5 commented Jun 15, 2017 reply Follow Share So that's why i mentioned both b and c.I have added e option also.Now answer should be bce as per me. 0 votes 0 votes Utkarsh Joshi commented Dec 8, 2018 reply Follow Share whats the answer for this question? 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes Here as it is intersection so the order mmsut divide both H and K here 3,20,4 does not divide 10 B,C,E should be the answer No_name answered Jun 19, 2017 No_name comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes According to lagranges theorem the order of a subgroup must be a divisor of the group. And the intersection of two subgroups will also be a subgroup of the main group,which is a property as well. Hence the answer is c. Krishnakant yadav answered Aug 21, 2017 Krishnakant yadav comment Share Follow See all 0 reply Please log in or register to add a comment.