0 votes 0 votes Mathematical Logic combinatory discrete-mathematics kenneth-rosen generating-functions + – rahul sharma 5 asked Jun 18, 2017 edited Mar 4, 2019 by Pooja Khatri rahul sharma 5 816 views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply rahul sharma 5 commented Jun 18, 2017 reply Follow Share for e:) my answer is ( (-2)^n )/n! -1 ,but given is ( (-2)^n )+n! 0 votes 0 votes Niraj Singh 2 commented Jun 19, 2017 reply Follow Share can i c ur solution 0 votes 0 votes rahul sharma 5 commented Jun 22, 2017 reply Follow Share Please check where am i mistaking? 0 votes 0 votes Niraj Singh 2 commented Jun 22, 2017 i edited by Niraj Singh 2 Jun 22, 2017 reply Follow Share why r u writing an in formula? , it is an, in part (e), at last step , u forgot to write n! in denominator. in part (f), for 1/(1+x), an will be (-1)n 0 votes 0 votes rahul sharma 5 commented Jun 22, 2017 reply Follow Share The question is same as https://gateoverflow.in/133771/discrete-maths-exponent-generating-function .So i am removing n! in the end to ge only an. You mentioned t is an ,which t are you talking about? My answer for e:) is not matching. It is given ( (-2)^n )+n! . Why is this + before n! ?. 0 votes 0 votes bhuv commented Sep 9, 2017 reply Follow Share For e part, I think your answer is correct as $a_{n}=\frac{(-2)^{n}}{n!} -1$. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes 1.(-2)$^{r}$ /r!-1 2.(-3)$^{r}$/r! -(-1)$^{r}$+2$^{r}$ 3.a$^{r_{_{}}}$={ 1/r! when r=2k ^ k>=0 else 0 Use e^x series generating function to generate these Psy Duck answered Dec 17, 2022 Psy Duck comment Share Follow See all 0 reply Please log in or register to add a comment.