if u r aware with sin(x) graph then u can directly say answer is b
now see rational proof:
f(x)=sinx , f'(x)=cos(x) , f"(x)=-sin(x)
put f'(x)=0
cos(x)=0
therefore x=n(pi)+pi/2, hence f"(x)=-sin(n*pi+pi/2)= -cos(n*pi)
therefore for all odd values of n, f"(x) will be positive hence local minima will occur here
now in given question if x=3pi/2 i.e x= pi+pi/2 therefore n= 1 (odd) option b is correct
5174 Points
4730 Points
3504 Points
3492 Points
3188 Points
2700 Points
2432 Points
2244 Points
2090 Points
1874 Points
Gatecse
thanks for these Motivating words ...
You can also upload COURSE AND ...