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What can we say about e^-x ?

a. Function is increasing at increasing rate

b. Function is decreasing at increasing rate

c. Function is increasing at decreasing  rate

d. Function is decreasing  at decreasing  rate

1 Answer

Best answer
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Answer should be D. Function is decreasing at decreasing rate.

Sign of first derivative tells whether a function is increasing or decreasing at particular point.

$\frac{\mathrm{d}}{\mathrm{d} x} e^{-x}= -e^{-x}$

At every point the derivative is negative, hence the function is decreasing.

Second derivative at particular point measures how fast the function is changing at that point.

$\frac{\mathrm{d^2}}{\mathrm{d} x^2} e^{-x}= e^{-x} = \frac{1}{e^x}$

As x increases the rate of change of $e^{-x}$ i.e. $\frac{1}{e^x}$ decreases. Hence the answer D. Function is decreasing at decreasing rate.
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