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L= {w |  na(w)=nb(w)} // DCFL

L' ={w |  na(w)!=nb(w)} // ?

DCFL is closed under Complement

so L' is DCFL too in that way.

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ggwon asked Dec 29, 2022
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L = {$a^{n+m}b^{n}a^{m} | n,m \geq 0$}Is the above language DCFL or CFL ?