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Resister set size 480

Number of bits required= 9

Instruction Register size =24 bits

$2^{24}$= $48*2^{18}$+$X*2^{9}$+2048

Total address possible = 2 address + 1 address + zero address

solving this we will get X=8188

So 8188 maximum 1-address possible
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If a 16-way Set Associative cache is made up of 64 bit words , 16 words per line and 8192 sets,How big is the cache in Megabytes ?