+1 vote
854 views

Consider the following circuit:

The flip-flops are positive edge triggered D FFs. Each state is designated as a two-bit string $Q_0Q_1$. Let the initial state be 00. The state transition sequence is

recategorized | 854 views

Clearly Q0 alternates in every clk cycle as Q0' is fed as input and it is D flipflop.

Q1 becomes 1 if its prev value and current Q0 differs (EXOR).

So, the sequence of transitions will be 00 -> 11 -> 01 -> 10 -> 00 (D) choice.

selected by
sir ,answer should be (D) ..

Q0next = D0= Q0'

Q1next = D1= Q0XORQ1'=Q0 XNOR Q1.

Q0Q1 = 00-->11--->01-->10-->00
Yes. I was taking OR Gate. Corrected now. Thanks..
My pleasure ...sir :)
sequence is 00->11->10->01
edited