No of balls = 3 identical red, 3 identical blue, 4 identical green.
Urns = U1, U2, U3.
Now my doubt here is that we can arrange all these 10 balls in those 3 urns as C(10+3-1, 3-1) or C(10+3-1,10), but consider a urn which has content as 2 red balls and 2 green balls.
which can be arranged in:-
fact(4)/ { fact(2) * fact(2) } = 6
but in through this formula:-
C(10+3-1, 3-1)
we are calculating 6 different permutations as 1 in that urn. And similar happening with other urns also.
So, how we can resolve such kind of question?