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This matrix is singular with rank one. Find three $λ$’s and three eigenvectors.

$\begin{bmatrix}1\\2 \\1 \end{bmatrix}$ $\begin{bmatrix}2&1 &2 \end{bmatrix}$ =  $\begin{bmatrix}2 & 1 &2\\4 & 2 & 4\\2 & 1 &2\end{bmatrix}$
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λ= 0,0,6 and respective eigen_vectors are,

[k1,  k2,  -k1-k2/2],  [k1,  k2,  -k1-k2/2],  k[1, 2, 1].........

where k1, k2 and k are arbitrary constants..

4 Comments

@Joshi_Nitish ,I think for  λ= 0 , Eigen vector  should be [k1,  k2,  (-2k1-k2)/2] ..

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(-2k1-k2)/2 = -k1-k2/2 

isn't it?

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ohh sorry.. I read it wrong..
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