Explain what is wrong with the statement that in the Monty Hall Three-Door Puzzle the probability that the prize is behind the first door you select and the probability that the prize is behind the other of the two doors that Monty does not open are both 1/2, because there are two doors left.

Question

the number of bit strings of length 8 that will either start with 1 or end with 00 is?

a) 32              b) 128              c) 160             d)192

Answer 1

the statement is wrong . first for all the other i just explain the puzzle . the puzzle just says that there is a show in which a candidate have to choose a door out of 3 doors. one door contain the gift let it be car and others to be goat . the host of the show know which door contain a gift. after choosing the one door . the host not directly open the door but open one of the remaining two door with a goat .and then the user is again given a choice to either stick to the earlier door or he can now choose the second door.

 the statement is wrong as there is equally likely probability of gift behind any door. so the probability will be 1/3 for each door. and the probability of gift behind the door you have selected is 1/3 and the probability of gift behind the 2 doors monty have not opened yet will be 2/3.

the answer end here . but for real life situation i u sometime get to that show somehow . the trick to win is alays change the door . after monty opens the door with a goat . as your winning changes are still 1/3 if u stick to your door . but the other set changes were 2/3 but now as there is only one door left in that set he probability is still 2/3 so good to go with more probability.