373 views

1 Answer

0 votes
0 votes

false,,,,,, becoz u r using biconditional (iff)

we know any row/column is constant multiple of any other row/column  ⇒ matrix is singular ,,,,is true

but other way 

A matrix is singular ⇒ any row/column is constant multiple of any other row/column ,,,,,,,,not neccesry condition

for example

 

|A| = 0(1-0) - 1(-1-0) + 1(0-1)

= 0

here matrix is singular but not any row/column is constant multiple of any other row/column.

so any row/column is constant multiple of any other row/column  ⇒ matrix is singular (only one way true)

Related questions

0 votes
0 votes
0 answers
2
rahul sharma 5 asked Jun 29, 2017
395 views
True /falseIf any row/column is constant is constant multiple of any other row/column then determinant is zero.Whether the converse of this statement is true or false?
0 votes
0 votes
1 answer
3
dragonball asked Jun 28, 2017
476 views
Suppose det(A)=4 then how we could find the det(a^4) ?A is a square matrix of order 4X4 .
1 votes
1 votes
1 answer
4
Desert_Warrior asked Jun 2, 2016
450 views