input-Output

Question

main ( )
{
int a = 2, b, c;
a* = b = c = 4;
a = b = c;
printf (“%d”, a);
a = = (b = c);
printf (“%d”, a);
}
What will be the output?
Not able to understand !!

Comments

it's is 4,4??

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Explain please..

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This would give compile time error.

Initially a = 2 and b , c are not yet initialized.

moving further in line 2 a* = b = c = 4;

a*=b is shorthand for a = a*b.

So, a*=b=c=4 implies a = a*b = c= 4;

Considering the precedence "*" should be evaluated before "=" but "b" is not initialized yet.

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@Bhavisha No. It is not giving any error. The output is 44

Answer 1

Ignore variable d, and values mentioned in block 1 for b and c are garbage values.

Comments

" a=(b==c);" : program does not have any statement like this rather if you are talking about a==(b=c) this statement in the program does not make any difference .

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thus, answer remains 44?

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Yup ! I think so ! Compile it for better understanding ! Hope it helps