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Given answer is (a) but L->AB i think it is wrong because A and B produce something else Previously,

 so instead of L->AB there would have given like L->MN

 M->c1 and N->S then it was correct . if I am wrong please correct me.

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Mk Utkarsh asked Mar 25, 2018
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Convert the given CFG to GNF.$S \rightarrow MN$$M\rightarrow aMb|\epsilon $$N\rightarrow aNb|\epsilon $