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A certain machine uses expanding opcode. It has 16-bit instructions and 6-bit addresses. It supports one address and two address instructions only. If there are ‘n’ two address instructions, the maximum number of one address instruction is
(a) 2^16 – n          (b) 2^10 – n
(c) (2^4 – n) × 2^6     (d) 2^10
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here it  is asking maximum no of 1 address instruction so we have to assume  that 2 address instruction will be 1
and so
maximum no of 1 instruction that can be possible will be (16-1)*2^6=960

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