Probability

Question

Suppose that in the production of 60-ohm radio
resistors, nondefective items are those that have a
resistance between 58 and 62 ohms and the probability
of a resistor’s being defective is 0.1%.The resistors
are sold in lots of 200, with the guarantee that all
resistors are nondefective. What is the probability that
a given lot will violate this guarantee? (Use the Poisson
distribution.)

Using bernoulli:18%

Comments

the probability= 1-$e^{-199.8}$*$\frac{(199.8)^{200}}{(200)!}$

but i think it cant be solved accurately since 200! is very large...

secondly, we use binomial distribution if exact probability is given(as in this case), and poisson distribution if average probabilty is given..

---

yes actually using bernoulli it can be solved easily .

---

@reena_kandari by bernoulli's distribution is it the value of C(200,1)*(0.001)*(1-0.001)^199?