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s=AQ' R=BQ{S=Q' R=0} A=1,B=0

:- here R is '0' always...

Initial value of Q :-??

case 1:-Q=0...then,  S=1,R=0{set condition in R-S ,therefor next sate of Q i.e Qn =1...

case 2:-let Q=1...then, S=0,R=0{latch condition in R-S, therefor next sate Qn={present state i.e 1}=1...

for both the cases Qn=1...so...option B is correct answer...

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