0 votes 0 votes Minimun number of comparison required to compute the largest and second largest element in array is A. n-[log₂n]-2 B. n+[log₂n-2] C. log₂n D. None of these Answer Report Discuss Indu123 asked Aug 20, 2017 Indu123 341 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.