2 votes 2 votes INFINITEPDA = {<M> | M is a PDA and L(M) is an infinite language } . Then - a) INFINITEPDA is undecidable. b) INFINITEPDA is decidable. c) INFINITEPDA is recursive enumerable. d) INFINITEPDA is Turing co-recognizable. Theory of Computation decidability theory-of-computation recursive-and-recursively-enumerable-languages + – amrendra pal asked Aug 20, 2017 amrendra pal 879 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Make variables vertices of the graph. An edge from $V_{i}$ to $V_{j}$ iff there exists a production having $V_{i}$ at the left & $V_{j}$ at the right for the grammar of $L(M)$. If there is a cycle in the graph $L(M)$ is infinite, otherwise not. Hence, IMO given language is decidable. Aghori answered Aug 20, 2017 Aghori comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments amrendra pal commented Aug 20, 2017 reply Follow Share @Aghori , can you give the whole explanation of the above question. 0 votes 0 votes Aghori commented Aug 20, 2017 reply Follow Share Given language (say A) is a set of PDAs having infinite language. Now tell whether given language (A) is decidable or not. 0 votes 0 votes amrendra pal commented Aug 20, 2017 reply Follow Share A is decidable 0 votes 0 votes Please log in or register to add a comment.