315 views

1 Answer

Best answer
2 votes
2 votes

As far as y and z is concerned , we have no problem as they can be any binary string..But as far as z is concerned , it is given that it should be binary sum of y and z ..Then only the string :

x  =  y + z

is accepted by the language else not..So for that we need to have addition capability of the machine so that we can find out about whether x is equal to sum of y and z or not..

Then the given language reduces to :

L  =  { x = x | x is a binary string } which we know very well that it is a CSL and hence not regular..

So it is clear that the given language is not regular..

To know about whether it is CSL or not , we see that here addition of y and z needs to be performed which cannot be done by a linearly bounded automata but can be done by a Turing Machine..

Hence the given language is not CSL as well.. 

selected by

Related questions

0 votes
0 votes
1 answer
1
practicalmetal asked Mar 25, 2023
380 views
The solution to $X = r +Xs$ by Arden’s Lemma when s has ϵa) an infinite number of solutionsb) a finite number of solutionsc) is always uniqued) none
1 votes
1 votes
1 answer
2
atulcse asked Jan 28, 2022
488 views
Which of the following languages is/are regular?
5 votes
5 votes
3 answers
3
Hirak asked May 25, 2019
1,827 views
Consider the following statements:$S_1:\{(a^n)^m|n\leq m\geq0\}$$S_2:\{a^nb^n|n\geq 1\} \cup \{a^nb^m|n \geq1,m \geq 1\} $Which of the following is regular?$S_1$ only$S_2...