doubt

Question

# include<stdio.h>

int main()

{

short int c[5];

int i=0;

for(i=0;i<5;i++)

c[i]=400+i;

char*b=(char*)c;

printf("%d",*(b+8));

}

the ouput of the above program,when short int take 2B and character take 1B..Assume memory storage follows liitle endian architecture.

Comments

see this: https://stackoverflow.com/questions/45650291/output-of-the-following-c-code

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https://gateoverflow.in/173156/%23pointers

Answer 1

garbage values will be printed

Comments

no its answer is 148