1 votes 1 votes Q. Compute the approximate optimal window size when packet size 53 byte and round trip time (RTT) is 60 ms and bandwidth (BW)155 mbps (in byte) using sliding window protocol. Computer Networks computer-networks + – kallu singh asked Aug 25, 2017 kallu singh 762 views answer comment Share Follow See all 8 Comments See all 8 8 Comments reply Show 5 previous comments joshi_nitish commented Aug 25, 2017 reply Follow Share correct. 0 votes 0 votes Shubhanshu commented Aug 27, 2017 reply Follow Share why you are not using w= 1 + 2a 0 votes 0 votes Shubhanshu commented Nov 10, 2017 reply Follow Share @saxena0612 @joshi_nitish For maximum eff = 100% = 1 1 = $\frac{n*TT}{TT + 2PT}$ where n = window size. TT = 2.73 sec PT = 30 $\frac{n*2.73}{2.73 + 60}$ = 1 n = 22.97 taking floor value it is 22. If we take ceil value then it will be more than 100%. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes Hope you will get this...:) sandeepjkh answered Aug 25, 2017 sandeepjkh comment Share Follow See all 0 reply Please log in or register to add a comment.