doubt

Question

Suppose that we draw a card from a deck of 52 cards and replace it before the next draw. In how many ways can 10 cards be drawn so that the tenth card is a repetition of a previous draw.

Answer 1

We have 10 position out of which 9 position can have 52 choice

And last position have 1 choice

So $\large 52^{9}$*1

Comments

why only one choice at the last position? there are 9 previous draws, and all of them can result in 9 distinct cards. In this case, the last position will have 9 choices?