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Let us understand through Venn diagram :

Let x :  Number of students who play only cricket

    y  : Number of students who play both cricket and football

    z :  Number of students who play only football

    t  : Number of students who play neither of the games   =  400 - (x + y + z)

According to the question :

             400 - (x + y + z)  =   y - 26

==>        x + 2y + z   =  426               ............(1)

According to second constraint :

            z - y  + 400 - (x + y + z)  =  x - y + 400 - (x + y + z) + 40

==>      z   = x + 40                         ..........(2) 

Hence substituting (2)  in (1) , we have :

           2(x + y)   =  386

==>     x + y    =   386 / 2  =   193

So ,

Number of students who play football  =   y + z  =  y + x + 40

                                                                      =  193 + 40

                                                                      =  233

Hence number of students who play football      =  233

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