1 votes 1 votes If f(x) = |x-1| + |x-2| is not derivable at x = (a) x = 0 (b) x = 1,2 (c) x = 3 (d) none Dhanraj vishwakarma asked Sep 20, 2017 Dhanraj vishwakarma 457 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 1 votes 1 votes first break the function now u can see that f '(2+) != f '(2-) also f '(1+) != f '(1-) so not derivable at x = 1 and 2 pawan kumarln answered Sep 20, 2017 • selected Nov 2, 2017 by pawan kumarln pawan kumarln comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes X = 0 -> f[x]=3 X= 1 -> f[x]=1 X=2 -> f[x]=1 X=3 -> f[x]=3 So I think it's 1,2 as that's where the tint occurs in graph. Correct me if I am wrong. Vasu Srivastava answered Sep 20, 2017 Vasu Srivastava comment Share Follow See all 0 reply Please log in or register to add a comment.