0 votes 0 votes Let $A=\{x|-1< x<1\}=B.$ The function $f(x)=\dfrac{x}{2}$ from $A$ to $B$ is: injective surjective both injective and surjective neither injective nor surjective Others ugcnetcse-june2006-paper2 + – go_editor asked Mar 27, 2020 edited May 20, 2021 by soujanyareddy13 go_editor 475 views answer comment Share Follow See all 9 Comments See all 9 9 Comments reply Show 6 previous comments utk0203 commented Sep 30, 2017 reply Follow Share Ans :1) 0 votes 0 votes rishu_darkshadow commented Sep 30, 2017 reply Follow Share how..plz explain .. 0 votes 0 votes vg653 commented Mar 27, 2020 reply Follow Share It should be injective but not surjective. 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes y=x/2 // monotonic increasing =>one-one certainly.... linear polynomials are always one-one domain and range ∈ (-1,1) but here co domain ∈ (-1/2 ,1/2) so some elements won't be connected to any x.. so it's not an onto function... Rupendra Choudhary answered Sep 30, 2017 Rupendra Choudhary comment Share Follow See all 0 reply Please log in or register to add a comment.