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The page fault service time is 10 ms in a computer with average memory access time being 20 ns.If one page fault is generated for every 10memory accesses.What is the effective access time for the memory?

A)21 ns                B)30 ns

C)23 ns                D)35 ns

I am confused with the conversions.Could anybody answer this with proper explanation.

1 Answer

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EMAT = p*(pfst) + (1 - p)*memory access time

where pfst = page fault service time

and p = page fault rate

Coming to your question,

EMAT = $\frac{1}{10^{6}}$*(10 ms) + (1 - $\frac{1}{10^{6}}$)*20 ns

         = 10 ns+ 20 ns  ( $\because$ $\frac{1}{10^{6}}$ is negligible as compared to 1 )

         = 30 ns

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