1 votes 1 votes The characteristic equation of a $\text{JK}$ flip-flop is : $Q_{n+1}=J\cdot Q_{n}+K\cdot Q_{n}$ $Q_{n+1}=J\cdot \bar{Q}_{n}+\bar{K}\cdot Q_{n}$ $Q_{n+1}={Q}_{n}+J\cdot K$ $Q_{n+1}=\left ( J+K \right )Q_{n}$ Digital Logic ugcnetcse-june2009-paper2 digital-logic flip-flop + – rishu_darkshadow asked Sep 22, 2017 • retagged Jul 5, 2023 by Hira Thakur rishu_darkshadow 2.2k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 3 votes 3 votes J K Qn Qn+1 0 0 0 0 0 0 1 1 0 1 0 0 0 1 1 0 1 0 0 1 1 0 1 1 1 1 0 1 1 1 1 0 Solve By K-Map gives Qn+1=J.Q’n+K’.Qn Answer B Shivam Chauhan answered Sep 22, 2017 • selected Sep 22, 2017 by sourav. Shivam Chauhan comment Share Follow See all 0 reply Please log in or register to add a comment.