3 votes 3 votes Suppose it takes $100$ ns to access a page table and $20$ ns to access associative memory with a $90$% hit rate, the average access time equals : $28$ $20$ $90$ $100$ Operating System ugcnetcse-june2009-paper2 operating-system effective-memory-access + – Sanjay Sharma asked Jan 3, 2017 edited Jun 23, 2022 by Arjun Sanjay Sharma 3.8k views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply santhoshdevulapally commented Jan 3, 2017 reply Follow Share 28?? 2 votes 2 votes G.K.T commented Sep 24, 2017 reply Follow Share shouldn't it be .9 x 20 + .1 x 120 as we are going to look at page table after looking in TLB and founding nothing there. 1 votes 1 votes Please log in or register to add a comment.
Best answer 4 votes 4 votes access time = time for associative memory * hit ratio + time for main memory = 20*0.9 + 100(1-0.9) =28ns sudsho answered Jan 3, 2017 selected Jan 3, 2017 by Sanjay Sharma sudsho comment Share Follow See 1 comment See all 1 1 comment reply rajatmyname commented Feb 21, 2019 reply Follow Share shouldn't it be .9 x 20 + .1 x 120 as we are going to look at page table after looking in TLB and founding nothing there. 1 votes 1 votes Please log in or register to add a comment.