answer should be does not exist , but in rd sharma answer is 1/ 8 root(3) how -_-

Question

limit              root (   1 + root (2+x)  - root (3)  )   /  ( x -2 )  

 

x --->2

Comments

answer would be $\frac{1}{8\sqrt{3}}$

if qsn would be    x--->2 $\frac{\sqrt{1+\sqrt{2+x}}-\sqrt{3}}{x-2}$

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yes thanks bro , it was a printing mistake