0 votes 0 votes Suppose it takes $100$ $ns$ to access page table and $20$ $ns$ to access associative memory. If the average access time is $28$ $ns$, the corresponding hit rate is: $100$ percent $90$ percent $80$ percent $70$ percent Computer Networks ugcnetcse-dec2008-paper2 computer-networks cache-memory + – rishu_darkshadow asked Sep 25, 2017 edited Jun 19, 2020 by soujanyareddy13 rishu_darkshadow 764 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes page table access time=100 ns memory access time=20 ns average access time= 28 ns, let hit rate be h avg memory access time= h X memory access time + (1-h) X page table access time 28=h X 20 + (1-h)100 h=90% Raushank2 answered Sep 25, 2017 Raushank2 comment Share Follow See 1 comment See all 1 1 comment reply G.K.T commented Sep 25, 2017 reply Follow Share Why not penalty time should be (100+20) 20 for looking in associative memory missed now go to page table 100 so total it would take 120. 0 votes 0 votes Please log in or register to add a comment.