27 votes 27 votes Consider the following Boolean expression for F: $F(P,Q,R,S)= PQ + \bar{P}QR + \bar{P}Q\bar{R}S$ The minimal sum$-$of$-$products form of $F$ is $PQ+QR+QS$ $P+Q+R+S$ $\bar{P} + \bar{Q}+ \bar{R}+ \bar{S}$ $\bar{P}R + \bar{R} \bar{P}S+P$ Digital Logic gatecse-2014-set1 digital-logic normal min-sum-of-products-form + – go_editor asked Sep 26, 2014 go_editor 8.3k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 38 votes 38 votes Minimal SOP $ = PQ + QR + QS$ Hence, option A is correct. amarVashishth answered Oct 9, 2015 edited Apr 27, 2019 by ajaysoni1924 amarVashishth comment Share Follow See all 0 reply Please log in or register to add a comment.
25 votes 25 votes so Option A is correct Çșȇ ʛấẗẻ answered Dec 11, 2016 Çșȇ ʛấẗẻ comment Share Follow See all 0 reply Please log in or register to add a comment.
8 votes 8 votes Solution: mohitbawankar answered Dec 6, 2017 mohitbawankar comment Share Follow See all 0 reply Please log in or register to add a comment.
4 votes 4 votes F= PQ+P’QR+P’QR’S =Q(P+P’+P’R’S) USE PROP a+a’b=a+b =Q(P+R+P’R’S) =Q(P+P’R’S+R) USE PROP a+a’b=a+b =Q(P+R’S+R) =Q(P+R+R’S) USE PROP a+a’b=a+b =Q(P+R+S) =PQ+QR+QS Ans (a) Regina Phalange answered Apr 6, 2017 Regina Phalange comment Share Follow See all 0 reply Please log in or register to add a comment.