D should be the correct answer.
Each Entry represents a row of table,in general.
In order to encode all the information of a row/entry, we must know what is the size of that information.But it is not mentioned in the question.
We can ADDRESS 287 entries by ceiling of Log2(287) = 9 bits.
but we CAN NOT ENCODE an entry, without knowing the size of that entry
So I don't think it is possible to tell how many bits are required to encode & transmit an entry unless any information is given about the data contained in entries.