3 votes 3 votes A nonpipeline system takes 50 ns to process a task. The same task can be processed in a six segment pipeline with a clock cycle of 10 ns. determine the speed up ratio of the pipeline for 100 tasks. a. 3.76 b. 4.76 c. 5.76 d. 2.76 CO and Architecture co-and-architecture pipelining speedup + – khushtak asked Oct 19, 2015 retagged Nov 13, 2017 by Arjun khushtak 13.5k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes S= ntn/(n+k-1)tp = 100*50/(100+6-1)*10 = 4.76 Option B Umang Raman answered Oct 19, 2015 selected Dec 15, 2015 by Pooja Palod Umang Raman comment Share Follow See 1 comment See all 1 1 comment reply vohraparth6 commented Nov 15, 2017 reply Follow Share S= ntn/(n+k-1)tp = 100*50/(100+6-1)*10 = 4.76 why n+k-1 ? 0 votes 0 votes Please log in or register to add a comment.