22 votes 22 votes Which one of the following circuits is NOT equivalent to a $2$-input $XNOR$ (exclusive $NOR$) gate? Digital Logic gatecse-2011 digital-logic normal digital-circuits + – go_editor asked Sep 29, 2014 edited Jun 19, 2018 by Pooja Khatri go_editor 5.5k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 28 votes 28 votes $(AB'+A'B)'=A\odot B$ $(A'(B')'+(A')'B')'=(A\oplus B)'=A\odot B$ $A'B'+(A')'B=A\odot B$ $((AB')'.(A+B'))'=(AB')+(A+B')'=AB'+A'B=A\oplus B$ So, Answer is (D) srestha answered Nov 8, 2016 edited Nov 5, 2018 by kenzou srestha comment Share Follow See 1 comment See all 1 1 comment reply Tuhin Dutta commented Sep 6, 2017 reply Follow Share $((A.B')'.(A+B'))' = A.B' + (A+B')' = A.B' + A'.B = A \oplus B$ I think this should be the expression. Please re-check your option D) @ srestha 1 votes 1 votes Please log in or register to add a comment.
7 votes 7 votes All options except D produce XNOR. See following image (Source: http://clweb.csa.iisc.ernet.in/rahulsharma/gate2011key.html) Source :GeeksforGeeks Pronomita Dey 1 answered Nov 4, 2017 edited Dec 25, 2017 by Pronomita Dey 1 Pronomita Dey 1 comment Share Follow See all 2 Comments See all 2 2 Comments reply SiddharthMahapatra commented Dec 25, 2017 reply Follow Share Correction : All options except D produce XNOR. 0 votes 0 votes Pronomita Dey 1 commented Jan 14, 2018 reply Follow Share Corrected, thank you. 1 votes 1 votes Please log in or register to add a comment.