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2 Answers

Best answer
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28 votes
  1. $(AB'+A'B)'=A\odot B$
  2. $(A'(B')'+(A')'B')'=(A\oplus B)'=A\odot B$
  3. $A'B'+(A')'B=A\odot B$
  4. $((AB')'.(A+B'))'=(AB')+(A+B')'=AB'+A'B=A\oplus B$


So, Answer is (D)

edited by
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7 votes
All options except D produce XNOR. See following image (Source: http://clweb.csa.iisc.ernet.in/rahulsharma/gate2011key.html)

 

 

 

Source :GeeksforGeeks
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