Answer -> Option B) 50
x>=4 and y>=4 , So we can take both x =5 & y = 5
x+y >= 10 => Satisfied , 5+5 = 10
2x + 3y >= 20. Satisfied.
This is infact minimum value.
Other options =>
4,4 => x+y constraint fail
4,5 => x+y fail
6,4 => Still giving 52 as sum which is more than 50 !, This can not be answer.
7,3 => 49+9 > 58 > 50.