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1 votes
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The mean of 100 observation is 50 and there standard deviation is 5. The sum of all squares of all the observation is

1) 50000

2) 250000

3) 252500

4) 25500

1 Answer

Best answer
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2 votes
All items are equally likely.

Let $\sigma$ be variance and $\mu$ be the mean.

$ \sigma =\Sigma_{i=1}^n \frac{(x_i - \mu)^2}{n} \\= \Sigma_{i=1}^n \frac{{x_i}^2}{n} - \Sigma_{i=1}^n \frac{2x_i \mu}{n} + \mu^2
\\=\Sigma_{i=1}^n \frac{{x_i}^2}{n} -2\mu^2 + \mu^2
\\=\Sigma_{i=1}^n \frac{{x_i}^2}{n} - \mu^2$

So, $\Sigma_{i=1}^n {{x_i}^2} = (\sigma + \mu^2) n \\= (5^2 + 2500) 100 \\=252500$
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