The differential equation
$\frac{dy}{dx}= y^{1/3}, y(0)=0$ has
dy/dx = y^{1/3}
or,∫dy/(y^{1/3}) =∫dx + c
or, y^{2/3} /(2/3) = x + c
or,3/2 . y^{2/3 }= x + c
or,3/2 . 0 = 0 + c
or, c=0
or, 3/2 . y^{2/3 }= x
Now say y=8, x=3/2 . 4 =6
Ans will be (D)
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Gatecse
@Arjun Sir the problem is not with the ...