Suppose, f is conti. at x = 0
As "0" is rational number f(x)= f(0)= 0
For any rational number x there exist a seq. Of Irrational xn converges to x .
Here, f is conti. f(xn) converges to f(x)
But f(xn) never converges to 0 so f is nowher conti.
Ans. True