First time here? Checkout the FAQ!
+2 votes
Where c is constant.
asked in Algorithms by (311 points)   | 293 views

1 Answer

+8 votes
Best answer

I am getting $\Theta$ (2^n) .

answered by Boss (7k points)  
selected by
You should use $\Theta$ though $O$ is not wrong here :)
Very nicely explained. Thanks for the answer. :)
Sir ,how to get the intution while solving a recurrence whether we should use theta or Big-O ?And why  here theta is more appropriate ?
Unless we approximate we always get $\Theta$. Theta says = while O says <=. So, Theta is more appropriate if it can be used.
But theta(n) is used when T(n) =Omega(n) as well as O(n) , so seeing the above solution how to conclude that both of them are asymptotically same .
Here, it is other way. In the proof all statements were "=". So, finally we can say it is $\Theta(2^n)$ and hence $O(2^n)$ and $\Omega(2^n)$.

Top Users Mar 2017
  1. rude

    4018 Points

  2. sh!va

    2994 Points

  3. Rahul Jain25

    2804 Points

  4. Kapil

    2606 Points

  5. Debashish Deka

    2092 Points

  6. 2018

    1414 Points

  7. Vignesh Sekar

    1318 Points

  8. Bikram

    1218 Points

  9. Akriti sood

    1166 Points

  10. Sanjay Sharma

    1004 Points

Monthly Topper: Rs. 500 gift card

21,439 questions
26,753 answers
22,930 users