1 votes 1 votes why this qs has no effect of two level paging??i dont know if the answer given by madeeasy is right.. CO and Architecture virtual-memory co-and-architecture + – resuscitate asked Jan 3, 2016 retagged Nov 13, 2017 by Arjun resuscitate 1.0k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Page table entry is nothing but the frame number. So the number of frames possible is $2^{16}$. Frame size = 1024 Bytes Physical memory supported = number of frames * frame size = $2^{16}\ast 1024 = 2^{26}$ Bytes = 64 MB Sandeep Singh answered Jan 3, 2016 Sandeep Singh comment Share Follow See all 5 Comments See all 5 5 Comments reply resuscitate commented Jan 3, 2016 reply Follow Share why 2 level paging is not required??i just want to know that??why the level paging concept is not using 0 votes 0 votes Sandeep Singh commented Jan 3, 2016 reply Follow Share because for main memory size you need only number of frames and frame size ( = page size). 0 votes 0 votes resuscitate commented Jan 3, 2016 i edited by resuscitate Jan 3, 2016 reply Follow Share arre i know that...without level paging,the problem is sitter...but it seems,they have given that for confusion only... 0 votes 0 votes Amit Pal commented Dec 2, 2016 reply Follow Share @sandeep . Page table entry may contain other info as well like valid/invalid bit onfo + dirty bit +protection bit . you cannot write like page table entry = no of frames . 0 votes 0 votes az7 commented Oct 29, 2019 reply Follow Share We can ignore those extra bits because in the question it is asking the maximum size of main memory supported. So the best-case scenario is that all 16 bits refer to the frame number. 0 votes 0 votes Please log in or register to add a comment.