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A fair coin is tossed three times in succession. If the first toss produces a head,
then the probability of getting exactly two heads in three tosses is

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A coin is tossed 3 times, if first toss produce a head, total cases, {HHH, HHT, HTH, HTT}. 

Probability of getting exactly two heads in 3 tosses, {HHT, HTH} , = $\frac{2}{4}  = \frac{1}{2}$

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