1 votes 1 votes A fair coin is tossed three times in succession. If the first toss produces a head, then the probability of getting exactly two heads in three tosses is Probability probability + – pC asked Jan 3, 2016 pC 1.1k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes A coin is tossed 3 times, if first toss produce a head, total cases, {HHH, HHT, HTH, HTT}. Probability of getting exactly two heads in 3 tosses, {HHT, HTH} , = $\frac{2}{4} = \frac{1}{2}$ Praveen Saini answered Jan 4, 2016 • selected Jan 4, 2016 by pC Praveen Saini comment Share Follow See 1 comment See all 1 1 comment reply smartmeet commented Dec 30, 2016 reply Follow Share Can we take like this, First is fixed so P(H)=1(always true) and cases are HHT and HTH so, 1*(1/2)[getting H]*(1/2)[getting T, not getting H] + 1*(1/2)[getting T, not getting H]*(1/2)[getting H] =1/4+1/4 =1/2 0 votes 0 votes Please log in or register to add a comment.