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2 votes
2 votes
 A and B are the only two stations on an Ethernet. Each has a steady queue of 
frames to send. Both A and B attempt to transmit a frame, collide, and A wins 
the first backoff race. At the end of this successful transmission by A, both A and B attempt to transmit and collide. The probability that A wins the second backoff race is 
(a) 0.5       (b) 0.625         (c) 0.75           (d) 1.0

2 Answers

Best answer
6 votes
6 votes
After 2nd Collison  a collision no =1 and B collision no=2(as A win first race)
So possible cases are
A   B
0    0
0    1
0    2
0    3
1    0
1    1
1    2
1    3
Thus p (a win 2nd Collison )=5/8=.625
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