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if d probability dat an individual suffers a bad reaction frm injection of a serum is 0.001.determine the probability that out of 2000 indivisuals exactly 3 individuals suffer a bad reaction?
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Use Binomial Distribution =nCr pn qn-r
put n=2000 r=3
p=0.001    q=1-p=0.999
Ans is 0.1805
correct me!!

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Its probability ques

binomial distribution applicable with poisson approximation ( n large p small)

mean(lambda)=n*p =2

apply poisson formula

(e ^ -2) *2^3/3¦ =. 18

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