Option a
As complement
m∨n=1 and m∧n=0
m∨p=1 and m∧p=0
So both n and p are complements of m
For distirbutive lattice
N∧(m∨p)= (N∧m)∨(N∧p)
From lhs. n∧(m∨p)=n∧1=n
From rhs. n∧m=0 n∧p=p
And 0∨p= p
So lhs≠ rhs that's why given lattice is non-distributive
S1: for lattice to be complemented there should exist LUB and GLB for pair of elements eg :(m,n) its LUB is 1 and its GLB is 0 S2: for a lattice to be distributive complement should be unique in above diagram we have two complements of m that is n,p so it is not distributive lattice so (A) option
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Gatecse
@Arjun Sir the problem is not with the ...