Total no. Of cycles= addition of followings-
{
For register 0.20*0
For immediate 0.20*0
Fo memory indirect 0.40*(8+8)=6.4
For auto indexed 0.20*(4+8)=2.4
}
Total no. Of cycles= 2.4+6.4=8.8cycles
Frequency 1ghz then cycle time=10-9 sec
Cpu time =total no.cycles*cycletime
Cpu time=8.8x10-9sec
Operand fetch rate(in million words per sec) =1/8.8x10-9sec
=113.636 M words per sec